Det Java String class compareTo() metode sammenligner den givne streng med den aktuelle streng leksikografisk. Det returnerer et positivt tal, negativt tal eller 0.
Den sammenligner strenge på basis af Unicode-værdien for hvert tegn i strengene.
Hvis den første streng er leksikografisk større end den anden streng, returnerer den et positivt tal (forskel i tegnværdi). Hvis den første streng er mindre end den anden streng leksikografisk, returnerer den et negativt tal, og hvis den første streng er leksikografisk lig med den anden streng, returnerer den 0.
if s1 > s2, it returns positive number if s1 <s2, 0 it returns negative number if s1="=" s2, < pre> <h3>Syntax</h3> <pre> public int compareTo(String anotherString) </pre> <p>The method accepts a parameter of type String that is to be compared with the current string.</p> <p>It returns an integer value. It throws the following two exceptions:</p> <p> <strong>ClassCastException:</strong> If this object cannot get compared with the specified object.</p> <p> <strong>NullPointerException:</strong> If the specified object is null.</p> <h2>Internal implementation</h2> <pre> int compareTo(String anotherString) { int length1 = value.length; int length2 = anotherString.value.length; int limit = Math.min(length1, length2); char v1[] = value; char v2[] = anotherString.value; int i = 0; while (i <limit) { char ch1="v1[i];" ch2="v2[i];" if (ch1 !="ch2)" return - ch2; } i++; length1 length2; < pre> <h2>Java String compareTo() Method Example</h2> <p> <strong>FileName:</strong> CompareToExample.java</p> <pre> public class CompareToExample{ public static void main(String args[]){ String s1='hello'; String s2='hello'; String s3='meklo'; String s4='hemlo'; String s5='flag'; System.out.println(s1.compareTo(s2));//0 because both are equal System.out.println(s1.compareTo(s3));//-5 because 'h' is 5 times lower than 'm' System.out.println(s1.compareTo(s4));//-1 because 'l' is 1 times lower than 'm' System.out.println(s1.compareTo(s5));//2 because 'h' is 2 times greater than 'f' }} </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 0 -5 -1 2 </pre> <h2>Java String compareTo(): empty string</h2> <p>When we compare two strings in which either first or second string is empty, the method returns the length of the string. So, there may be two scenarios:</p> <ul> <li>If <strong>first</strong> string is an empty string, the method returns a <strong>negative</strong> </li> <li>If <strong>second</strong> string is an empty string, the method returns a <strong>positive</strong> number that is the length of the first string.</li> </ul> <p> <strong>FileName:</strong> CompareToExample2.java</p> <pre> public class CompareToExample2{ public static void main(String args[]){ String s1='hello'; String s2=''; String s3='me'; System.out.println(s1.compareTo(s2)); System.out.println(s2.compareTo(s3)); }} </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 5 -2 </pre> <h3>Java String compareTo(): case sensitive</h3> <p>To check whether the compareTo() method considers the case sensitiveness of characters or not, we will make the comparison between two strings that contain the same letters in the same sequence.</p> <p>Suppose, a string having letters in uppercase, and the second string having the letters in lowercase. On comparing these two string, if the outcome is 0, then the compareTo() method does not consider the case sensitiveness of characters; otherwise, the method considers the case sensitiveness of characters.</p> <p> <strong>FileName:</strong> CompareToExample3.java</p> <pre> public class CompareToExample3 { // main method public static void main(String argvs[]) { // input string in uppercase String st1 = new String('INDIA IS MY COUNTRY'); // input string in lowercase String st2 = new String('india is my country'); System.out.println(st1.compareTo(st2)); } } </pre> <p> <strong>Output:</strong> </p> <pre> -32 </pre> <p> <strong>Conclusion:</strong> It is obvious by looking at the output that the outcome is not equal to zero. Hence, the compareTo() method takes care of the case sensitiveness of characters.</p> <h3>Java String compareTo(): ClassCastException</h3> <p>The <strong>ClassCastException</strong> is thrown when objects of incompatible types get compared. In the following example, we are comparing an object of the ArrayList (al) with a string literal ('Sehwag').</p> <p> <strong>FileName:</strong> CompareToExample4.java</p> <pre> // import statement import java.util.*; class Players { private String name; // constructor of the class public Players(String str) { name = str; } } public class CompareToExample4 { // main method public static void main(String[] args) { Players ronaldo = new Players('Ronaldo'); Players sachin = new Players('Sachin'); Players messi = new Players('Messi'); ArrayList al = new ArrayList(); al.add(ronaldo); al.add(sachin); al.add(messi); // performing binary search on the list al Collections.binarySearch(al, 'Sehwag', null); } } </pre> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.ClassCastException: class Players cannot be cast to class java.lang.Comparable </pre> <h3>Java String compareTo(): NullPointerException</h3> <p>The NullPointerException is thrown when a null object invokes the compareTo() method. Observe the following example.</p> <p> <strong>FileName:</strong> CompareToExample5.java</p> <pre> public class CompareToExample5 { // main method public static void main(String[] args) { String str = null; // null is invoking the compareTo method. Hence, the NullPointerException // will be raised int no = str.compareTo('India is my country.'); System.out.println(no); } } </pre> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.NullPointerException at CompareToExample5.main(CompareToExample5.java:9) </pre> <hr></limit)></pre></s2,> Metoden accepterer en parameter af typen String, der skal sammenlignes med den aktuelle streng.
Det returnerer en heltalsværdi. Det giver følgende to undtagelser:
ClassCastException: Hvis dette objekt ikke kan sammenlignes med det angivne objekt.
NullPointerException: Hvis det angivne objekt er null.
netværkslag i computernetværk
Intern implementering
int compareTo(String anotherString) { int length1 = value.length; int length2 = anotherString.value.length; int limit = Math.min(length1, length2); char v1[] = value; char v2[] = anotherString.value; int i = 0; while (i <limit) { char ch1="v1[i];" ch2="v2[i];" if (ch1 !="ch2)" return - ch2; } i++; length1 length2; < pre> <h2>Java String compareTo() Method Example</h2> <p> <strong>FileName:</strong> CompareToExample.java</p> <pre> public class CompareToExample{ public static void main(String args[]){ String s1='hello'; String s2='hello'; String s3='meklo'; String s4='hemlo'; String s5='flag'; System.out.println(s1.compareTo(s2));//0 because both are equal System.out.println(s1.compareTo(s3));//-5 because 'h' is 5 times lower than 'm' System.out.println(s1.compareTo(s4));//-1 because 'l' is 1 times lower than 'm' System.out.println(s1.compareTo(s5));//2 because 'h' is 2 times greater than 'f' }} </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 0 -5 -1 2 </pre> <h2>Java String compareTo(): empty string</h2> <p>When we compare two strings in which either first or second string is empty, the method returns the length of the string. So, there may be two scenarios:</p> <ul> <li>If <strong>first</strong> string is an empty string, the method returns a <strong>negative</strong> </li> <li>If <strong>second</strong> string is an empty string, the method returns a <strong>positive</strong> number that is the length of the first string.</li> </ul> <p> <strong>FileName:</strong> CompareToExample2.java</p> <pre> public class CompareToExample2{ public static void main(String args[]){ String s1='hello'; String s2=''; String s3='me'; System.out.println(s1.compareTo(s2)); System.out.println(s2.compareTo(s3)); }} </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 5 -2 </pre> <h3>Java String compareTo(): case sensitive</h3> <p>To check whether the compareTo() method considers the case sensitiveness of characters or not, we will make the comparison between two strings that contain the same letters in the same sequence.</p> <p>Suppose, a string having letters in uppercase, and the second string having the letters in lowercase. On comparing these two string, if the outcome is 0, then the compareTo() method does not consider the case sensitiveness of characters; otherwise, the method considers the case sensitiveness of characters.</p> <p> <strong>FileName:</strong> CompareToExample3.java</p> <pre> public class CompareToExample3 { // main method public static void main(String argvs[]) { // input string in uppercase String st1 = new String('INDIA IS MY COUNTRY'); // input string in lowercase String st2 = new String('india is my country'); System.out.println(st1.compareTo(st2)); } } </pre> <p> <strong>Output:</strong> </p> <pre> -32 </pre> <p> <strong>Conclusion:</strong> It is obvious by looking at the output that the outcome is not equal to zero. Hence, the compareTo() method takes care of the case sensitiveness of characters.</p> <h3>Java String compareTo(): ClassCastException</h3> <p>The <strong>ClassCastException</strong> is thrown when objects of incompatible types get compared. In the following example, we are comparing an object of the ArrayList (al) with a string literal ('Sehwag').</p> <p> <strong>FileName:</strong> CompareToExample4.java</p> <pre> // import statement import java.util.*; class Players { private String name; // constructor of the class public Players(String str) { name = str; } } public class CompareToExample4 { // main method public static void main(String[] args) { Players ronaldo = new Players('Ronaldo'); Players sachin = new Players('Sachin'); Players messi = new Players('Messi'); ArrayList al = new ArrayList(); al.add(ronaldo); al.add(sachin); al.add(messi); // performing binary search on the list al Collections.binarySearch(al, 'Sehwag', null); } } </pre> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.ClassCastException: class Players cannot be cast to class java.lang.Comparable </pre> <h3>Java String compareTo(): NullPointerException</h3> <p>The NullPointerException is thrown when a null object invokes the compareTo() method. Observe the following example.</p> <p> <strong>FileName:</strong> CompareToExample5.java</p> <pre> public class CompareToExample5 { // main method public static void main(String[] args) { String str = null; // null is invoking the compareTo method. Hence, the NullPointerException // will be raised int no = str.compareTo('India is my country.'); System.out.println(no); } } </pre> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.NullPointerException at CompareToExample5.main(CompareToExample5.java:9) </pre> <hr></limit)> Test det nu Produktion:
0 -5 -1 2
Java String compareTo(): tom streng
Når vi sammenligner to strenge, hvor enten første eller anden streng er tom, returnerer metoden længden af strengen. Så der kan være to scenarier:
- Hvis først streng er en tom streng, metoden returnerer en negativ
- Hvis anden streng er en tom streng, metoden returnerer en positiv tal, der er længden af den første streng.
Filnavn: CompareToExample2.java
public class CompareToExample2{ public static void main(String args[]){ String s1='hello'; String s2=''; String s3='me'; System.out.println(s1.compareTo(s2)); System.out.println(s2.compareTo(s3)); }} Test det nu Produktion:
5 -2
Java String compareTo(): følsomme mellem store og små bogstaver
For at kontrollere, om compareTo()-metoden tager højde for følsomheden af store og små bogstaver eller ej, vil vi foretage sammenligningen mellem to strenge, der indeholder de samme bogstaver i samme rækkefølge.
Antag, at en streng har bogstaver med store bogstaver, og den anden streng har bogstaverne med små bogstaver. Ved at sammenligne disse to strenge, hvis resultatet er 0, så tager compareTo()-metoden ikke hensyn til tegns følsomhed mellem store og små bogstaver; ellers tager metoden hensyn til karakterernes følsomhed over for store og små bogstaver.
Filnavn: CompareToExample3.java
public class CompareToExample3 { // main method public static void main(String argvs[]) { // input string in uppercase String st1 = new String('INDIA IS MY COUNTRY'); // input string in lowercase String st2 = new String('india is my country'); System.out.println(st1.compareTo(st2)); } } Produktion:
do and while loop i java
-32
Konklusion: Det er tydeligt ved at se på outputtet, at resultatet ikke er lig med nul. Derfor tager compareTo()-metoden sig af bogstavernes følsomhed over for store og små bogstaver.
Java String compareTo(): ClassCastException
Det ClassCastException kastes, når objekter af inkompatible typer sammenlignes. I det følgende eksempel sammenligner vi et objekt i ArrayList (al) med en streng-literal ('Sehwag').
Filnavn: SammenlignTilEksempel4.java
// import statement import java.util.*; class Players { private String name; // constructor of the class public Players(String str) { name = str; } } public class CompareToExample4 { // main method public static void main(String[] args) { Players ronaldo = new Players('Ronaldo'); Players sachin = new Players('Sachin'); Players messi = new Players('Messi'); ArrayList al = new ArrayList(); al.add(ronaldo); al.add(sachin); al.add(messi); // performing binary search on the list al Collections.binarySearch(al, 'Sehwag', null); } } Produktion:
Exception in thread 'main' java.lang.ClassCastException: class Players cannot be cast to class java.lang.Comparable
Java String compareTo(): NullPointerException
NullPointerException kastes, når et null-objekt kalder compareTo()-metoden. Bemærk følgende eksempel.
Filnavn: CompareToExample5.java
public class CompareToExample5 { // main method public static void main(String[] args) { String str = null; // null is invoking the compareTo method. Hence, the NullPointerException // will be raised int no = str.compareTo('India is my country.'); System.out.println(no); } } Produktion:
Exception in thread 'main' java.lang.NullPointerException at CompareToExample5.main(CompareToExample5.java:9)